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Timeline for 〈x,y : x^p = y^p = (xy)^p = 1〉

Current License: CC BY-SA 2.5

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when toggle format what by license comment
May 8, 2010 at 3:51 comment added Steve D $(ab)^{(p-1)/2}[-p+2]=-p+1$.
May 7, 2010 at 22:28 history answered G B CC BY-SA 2.5