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May 8, 2010 at 12:54 comment added Matthew Morrow I almost added a caveat to my reply that $A$ was assumed to be Noetherian, but decided not to on the grounds that the question was about Noetherian schemes. Next time I will be more careful!
May 8, 2010 at 7:46 comment added Matthieu Romagny To be irreproachable, one should in fact say : a finitely $presented$ $A$-module is locally free if and only if it is flat. There are examples of surjective, non-finitely presented morphisms of local rings that are flat.
May 7, 2010 at 22:51 history edited Matthew Morrow CC BY-SA 2.5
added 100 characters in body
May 7, 2010 at 22:08 history answered Matthew Morrow CC BY-SA 2.5