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May 16, 2016 at 21:37 vote accept Matthias Ludewig
May 16, 2016 at 6:35 answer added András Bátkai timeline score: 4
May 16, 2016 at 6:26 comment added András Bátkai If $B$ is unbounded, then this is never a semigroup generator. You have to work in a different product space, the so-called energy space.
May 15, 2016 at 23:18 comment added Liviu Nicolaescu For nonlinear semigroups see the paper by V. Barbu: Sur un problème aux limites pour une classe d'équations différentielles non linéaires abstraits du deuxième ordre en $t$. (French) C. R. Acad. Sci. Paris Sér. A-B 274 (1972)
May 15, 2016 at 23:12 comment added Liviu Nicolaescu The Hille-Yosida theory applies to the operator $B$ as well. See for example Sec.10.3 of Brezis' book Functional Analysis, Sobolev Spaces and Partial Differential Equations
May 15, 2016 at 21:35 history asked Matthias Ludewig CC BY-SA 3.0