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S Apr 9, 2021 at 7:06 history bounty ended CommunityBot
S Apr 9, 2021 at 7:06 history notice removed CommunityBot
Apr 3, 2021 at 17:17 answer added Gerald Edgar timeline score: 1
Apr 2, 2021 at 16:32 comment added Gerald Edgar I added my example. Levi-Cevita did not work, you need more (and less). The added question about "defined by a valuation" would be interesting.
Apr 2, 2021 at 6:28 comment added Uri Bader @GeraldEdgar My question regards indeed $[0,\infty)$ valued absolute values, but I certainly welcome more generous interpretation of it, eg: "Is every Polish ring topology on C defined by a valuation?". I do not understand your suggestion regarding the Levi-Civita field - Isn't it defined by a valuation a priori?
Apr 1, 2021 at 15:17 comment added Gerald Edgar Your absolute value has values in $[0,+\infty)$? Maybe for a counterexample try the Levi-Civita field (extended by adding $i$). Maybe we get a larger value group.
S Apr 1, 2021 at 6:06 history bounty started Noah Schweber
S Apr 1, 2021 at 6:06 history notice added Noah Schweber Draw attention
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
May 14, 2016 at 15:47 history edited Uri Bader
edited tags
May 14, 2016 at 15:31 comment added Uri Bader @YCor, thanks for your comments. An edit was made in order to clarify things.
May 14, 2016 at 15:30 history edited Uri Bader CC BY-SA 3.0
added 470 characters in body; edited title
May 13, 2016 at 22:23 comment added YCor By "comes from an absolute value", do you mean, given by a complete (multiplicative) norm?
May 13, 2016 at 22:22 comment added YCor About the note: in $\mathbf{C}$, the modular fonction yields $\Delta(2)=4$, while $|2|=2$.
May 13, 2016 at 22:18 history asked Uri Bader CC BY-SA 3.0