Timeline for GCD in polynomial vs. formal power series rings
Current License: CC BY-SA 3.0
9 events
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May 12, 2016 at 20:50 | history | edited | user91576 | CC BY-SA 3.0 |
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May 12, 2016 at 20:23 | history | edited | user91576 | CC BY-SA 3.0 |
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May 12, 2016 at 20:21 | comment | added | user91576 | Right, modulo multiplication by a unit. Editing the question. | |
May 12, 2016 at 19:45 | answer | added | Friedrich Knop | timeline score: 2 | |
May 12, 2016 at 19:42 | comment | added | Mohan | As abx says, there are some issues of comparison. But, it can be made sensible as follows. Writing $f=ah, g=bh$, with $a, b$ polynomials and $\mathrm{gcd}(a,b)=1$, suffices to show that the same holds in the power series. If $a(0)\neq 0$ or $b(0)\neq 0$, they are units in the power series and so this is alright. If both are zero, then use the fact that they form a regular sequence in the polynomial ring and so remain a regular sequence in the power series and thus have no common factor in the power series. | |
May 12, 2016 at 19:39 | comment | added | Friedrich Knop | What is meant is: Is a gcd in $\mathbb C[x_i]$ also a gcd in $\mathbb C[[x_i]]$? | |
May 12, 2016 at 19:26 | comment | added | abx | The g.c.d. is defined up to a unit. In $\mathbb{C}[x]$ this means up to a scalar, but in $\mathbb{C}[[x]]$ up to any formal series with nonzero constant term, so you can always find a g.c.d. of hte form $x^n$. Thus the comparison does not make much sense. | |
May 12, 2016 at 19:09 | review | First posts | |||
May 12, 2016 at 19:12 | |||||
May 12, 2016 at 19:07 | history | asked | user91576 | CC BY-SA 3.0 |