Timeline for The number of maximal subgroups up to isomorphism
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Jun 15, 2019 at 20:11 | comment | added | user6976 | The fact that $N\times N$ is maximal if $F/N $ is simple indeed follows from Baumslag and Roseblade. By their tesult every subgroup containing $N\times N $ corresponds to a proper factor of $F/N $. | |
| Aug 26, 2018 at 14:52 | history | edited | YCor | CC BY-SA 4.0 |
added reference
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| May 12, 2016 at 19:51 | comment | added | user6976 | @Igor: I do not think they mention maximal subgroups there, but they do prove that F x F contains uncountably many pairwise non-isomorphic subgroups. | |
| May 12, 2016 at 18:47 | comment | added | Igor Rivin | This is a theorem of Baumslag-Roseblade, 1984 | |
| May 12, 2016 at 17:54 | vote | accept | CommunityBot | moved from User.Id=6976 by developer User.Id=69903 | |
| May 12, 2016 at 16:23 | history | answered | YCor | CC BY-SA 3.0 |