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May 20, 2016 at 8:39 vote accept Serendipity
May 12, 2016 at 14:10 comment added Jeremy Rouse Yes, that's right - only odd dihedral representations.
May 12, 2016 at 13:48 comment added David E Speyer More precisely, dihedral extensions where complex conjugation acts by an element of determinant $-1$ -- otherwise you have to deal with ray class characters of real quadratic fields and you get Maas forms instead of modular forms.
May 12, 2016 at 13:47 comment added Jeremy Rouse I believe this method will work for all dihedral representations, and no others. The rough idea is that the space of weight 1 cusp forms spanned by differences of theta series should be decomposable into linear combinations of forms obtained from ray class characters of imaginary quadratic fields - these correspond by class field theory to dihedral extensions of $\mathbb{Q}$.
May 12, 2016 at 13:38 comment added Serendipity Thanks! It seems that all such "classic" solutions I have seen involve theta series. Will it work for all $S_3$ representations (or maybe even more)?
May 12, 2016 at 13:24 history answered Jeremy Rouse CC BY-SA 3.0