Timeline for Formula for an integration on $\mathbb{Q} \cap [0,1]$
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 12, 2016 at 20:12 | vote | accept | Bertrand | ||
| May 12, 2016 at 0:46 | comment | added | Gerald Edgar | For a function $f$ on $\mathbb{Q} \cap [0,1]$, the continuous extension to $[0,1]$ exists iff $f$ is uniformly continuous. | |
| May 11, 2016 at 22:09 | history | answered | Robert Israel | CC BY-SA 3.0 |