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May 11, 2016 at 16:13 answer added Gerhard Paseman timeline score: 2
May 11, 2016 at 15:59 comment added Geoff Robinson Since $p^{2} \equiv 1$ (mod $8$) for odd $p$, we can't have $2^{n} = p^{2}+1$, and more generally, $2^{n}= p^{k}+1$ gives that $k$ must be odd. Of course any Mersenne prime $p$ works with $k = 1$, so suppose $k > 1.$ However, it is easy to check that $\frac{p{k}+1}{p+1}$ is then odd, a contradiction. So the only solutions (to the second question) are when $p$ is a Mersenne prime and $k=1$. There are no solutions to the first question ( Obsolete by Douglas Zare's link to a more general answer).
May 11, 2016 at 15:46 comment added Douglas Zare en.wikipedia.org/wiki/Catalan%27s_conjecture
May 11, 2016 at 15:43 comment added Douglas Zare What is the connection to graph spectra?
May 11, 2016 at 15:42 review First posts
May 11, 2016 at 17:38
May 11, 2016 at 15:41 history asked user91523 CC BY-SA 3.0