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May 9, 2016 at 23:34 vote accept ike
May 9, 2016 at 22:56 comment added Bjørn Kjos-Hanssen @JasonRute can you also obtain that it is a low degree?
May 9, 2016 at 22:34 comment added Jason Rute One can even be a little more specific about $\textrm{deg}_T (\Gamma(\Omega))$. Since $\Gamma(\Omega)$ is truth-table reducible to a Martin-Löf random and is above $\mathbf{0}$, it follows that $\Gamma(\Omega)$ is Turing-equivalent to a Martin-Löf random by Demuth's theorem.
May 9, 2016 at 22:21 comment added Jason Rute Someone (they probably don't want to be named) recently told me that they knew of a new Turing degree which comes from Chaitin's $\Omega$. I don't remember their construction, but it was quite natural. However, they soon realized that they were mistaken since their construction would result in different Turing degrees based on which Gödel numbering one used to define $\Omega$.
May 9, 2016 at 18:25 history edited Bjørn Kjos-Hanssen CC BY-SA 3.0
more info
May 9, 2016 at 17:53 history answered Bjørn Kjos-Hanssen CC BY-SA 3.0