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Jun 5, 2016 at 1:16 vote accept D.R.
May 8, 2016 at 18:08 comment added Nate Eldredge Oh right. This is really just the fact that the weak topology on $\mathcal{P}(S)$ is second countable (since it's separable and metrizable).
May 8, 2016 at 13:14 history answered Dan CC BY-SA 3.0