Timeline for Separating Heavier from the Lighter Balls
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Dec 9, 2016 at 7:43 | vote | accept | Vepir | ||
May 7, 2016 at 17:11 | comment | added | David G. Stork | I would be interested in the answer to a modified question in which each weighing operation (on a pan balance, say) returns just either heavier, lighter or equal of the candidate sets--not their weight difference. | |
May 7, 2016 at 6:59 | comment | added | Vepir | That is great! So overall this solves the $2n$ cases in either $n+1$ or $n$ weightings. So far in my original question I've posted some "manual methods" for specific cases which seem to need exactly $n$ weightings or exactly the average of $n$ weightings up to the case of $10$ balls which I've found to do in either $4$ or $5$ weightings I believe, which averages out at $\approx 4.86$ weightings thus is even less than $n$, on average. But I think I need to double check and revise all my methods so far, and hopefully come up with something to follow the pattern of exactly $n$ weightings or less. | |
May 7, 2016 at 6:45 | history | edited | Tony Huynh | CC BY-SA 3.0 |
added 27 characters in body
|
May 6, 2016 at 23:12 | history | edited | Tony Huynh | CC BY-SA 3.0 |
added 21 characters in body
|
May 6, 2016 at 23:05 | history | edited | Tony Huynh | CC BY-SA 3.0 |
added 21 characters in body
|
May 6, 2016 at 21:23 | history | answered | Tony Huynh | CC BY-SA 3.0 |