Timeline for Example of a Schur-nontrivial group with no abelian subgroup of the form $H\times H$?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Jul 8, 2016 at 6:26 | comment | added | Lior Silberman | Every group of the form $H\times H$ contains an abelian one of the same form (take a cyclic subgroup of $H$) | |
| May 6, 2016 at 19:15 | vote | accept | David Stephen | ||
| May 3, 2016 at 18:55 | comment | added | David Stephen | You are correct, I am interested in finite groups. So your argument shows that if a finite G has a non-trivial Schur multiplier, then it must contain a subgroup of the form $H \times H$ for $H$ abelian. This is a very nice result, thank you. | |
| May 3, 2016 at 10:19 | history | edited | Jeremy Rickard | CC BY-SA 3.0 |
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| May 3, 2016 at 10:10 | history | answered | Jeremy Rickard | CC BY-SA 3.0 |