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May 3, 2016 at 14:41 answer added Allen Knutson timeline score: 7
May 3, 2016 at 8:06 vote accept Jianrong Li
May 3, 2016 at 6:54 answer added Friedrich Knop timeline score: 12
May 3, 2016 at 3:40 comment added Dave Witte Morris It is not true that $G = U_- B$ (unless $n = 1$, I guess). The set $U_- B$ is dense and open, but it is only the "big cell" of the Bruhat decomposition, and there are other (lower-dimensional) cells that are needed to get all of $G$. However, you are right that there is an embedding $\mathbb{C}[G/U_-] \hookrightarrow \mathbb{C}[B]$. (In your example, don't you also need the functions $g_{22}$, $g_{23}$, and $g_{33}$?)
May 3, 2016 at 3:28 history asked Jianrong Li CC BY-SA 3.0