Timeline for 4-th order diophantine equation
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Apr 30, 2016 at 13:31 | comment | added | veg_nw | @joro And could you please also share your thoughts about the mathoverflow.net/questions/236044/… | |
| Apr 30, 2016 at 13:29 | vote | accept | veg_nw | ||
| Apr 30, 2016 at 12:26 | comment | added | joro | @veg_nw I edited. | |
| Apr 30, 2016 at 12:26 | history | edited | joro | CC BY-SA 3.0 |
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| Apr 30, 2016 at 12:14 | comment | added | veg_nw | And does this mean that there is no general "non-polynominal" solutions exist as well? | |
| Apr 30, 2016 at 11:16 | history | edited | joro | CC BY-SA 3.0 |
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| Apr 30, 2016 at 11:11 | comment | added | joro | @LevBorisov Yes. This is not complete parametrization. Though setting $a'=c/d$ gives a point on the elliptic curve and remains to show it is of infinite order. | |
| Apr 30, 2016 at 11:09 | comment | added | Lev Borisov | @joro You mean apart from the silly stuff like $a=kc,b=kd$? | |
| Apr 30, 2016 at 11:07 | comment | added | joro | @veg_nw Yes, I am ready to bet polynomial solution doesn't exist. | |
| Apr 30, 2016 at 10:58 | comment | added | veg_nw | If I understand correctly the general solution does not exist? If this can be proven does this mean that there is no polynominal solution of this equation in general? | |
| Apr 30, 2016 at 10:51 | history | answered | joro | CC BY-SA 3.0 |