Timeline for what is the universal cover of GL(2,R)?

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Apr 13, 2017 at 12:19	history	edited	CommunityBot		replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
Apr 29, 2016 at 8:21	history	edited	Bombyx mori	CC BY-SA 3.0	added 14 characters in body
Apr 29, 2016 at 8:19	comment	added	Bombyx mori		@Thomas: Yes! I just realized this has been written down at here: math.uconn.edu/~kconrad/blurbs/grouptheory/SL(2,R).pdf
Apr 29, 2016 at 8:07	comment	added	Thomas		The KAN decomposition of $SL(2, \bf R)$ is $G=KAN$ with $K=SO(2)$ $A$ the set of diagonal matrices, $N$ the set of upper triangular matrices with $1$ on the diagonal. The universal cover map being explicitely given by ${\bf R} \times {\bf R}^+ \times {\bf R} \to Sl(2, {\bf R})$, $F(\theta, \lambda, u)=$$\left( \begin{array}{cc} cos \theta & sin \theta \\ -sin \theta & cos \theta\end{array} \right)\left( \begin{array}{cc} \lambda & 0 \\ 0 & \lambda ^{-1}\end{array} \right)\left( \begin{array}{cc} 1 & u \\ 0 & 1\end{array} \right)$
Apr 29, 2016 at 6:19	vote	accept	Matthias Volkov
Apr 29, 2016 at 5:14	history	edited	Bombyx mori	CC BY-SA 3.0	deleted 401 characters in body
Apr 29, 2016 at 5:14	comment	added	Qiaochu Yuan		The OP also says "and therefore $G'$ was $\mathbb{C}^2$" so I think it is clear he meant $\mathbb{C}^{\ast} = \mathbb{C} \setminus \{ 0 \}$. (I prefer the notation $\mathbb{C}^{\times}$.)
Apr 29, 2016 at 5:07	history	answered	Bombyx mori	CC BY-SA 3.0