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Andreas Thom
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Whenever $A$ is positivenegative semi-definite on the subspace of vectors $(a_1,\dots,a_n)$ with $\sum_i a_i=0$, then the same will be true for $B$. This is a result of Schoenberg.

Whenever $A$ is positive semi-definite on the subspace of vectors $(a_1,\dots,a_n)$ with $\sum_i a_i=0$, then the same will be true for $B$. This is a result of Schoenberg.

Whenever $A$ is negative semi-definite on the subspace of vectors $(a_1,\dots,a_n)$ with $\sum_i a_i=0$, then the same will be true for $B$. This is a result of Schoenberg.

Source Link
Andreas Thom
  • 25.5k
  • 4
  • 82
  • 142

Whenever $A$ is positive semi-definite on the subspace of vectors $(a_1,\dots,a_n)$ with $\sum_i a_i=0$, then the same will be true for $B$. This is a result of Schoenberg.