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Apr 13, 2017 at 12:19 history edited CommunityBot
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
Apr 29, 2016 at 16:46 comment added Juan Sebastian Lozano @IraGessel Oh, you're 100% right, I didn't even know OEIS had a formula section until you pointed it out. That's also probably what Alex Degtyarev was referring to too.
Apr 29, 2016 at 16:30 comment added Ira Gessel The formula a(n)=Sum_{k=0..[ n/2 ]} n!/((n-2*k)!*2^k*k!) is the fourth line of the OEIS "Formula" section.
Apr 27, 2016 at 12:34 comment added Juan Sebastian Lozano @ToddLeason I stand corrected, it is both trivial and well known. Thank you for linking to those places.
Apr 27, 2016 at 12:26 comment added Todd Leason See for example math.stackexchange.com/questions/795541/involutions-of-s-n or google for "number of involutions in symmetric group". BTW: According to the acctepted SE answer the product in your formular can be resolved.
Apr 27, 2016 at 11:42 comment added Juan Sebastian Lozano @AlexDegtyarev Although my idea of counting the number of graphs isn't novel (it's listed as Don Knuth's contribution on OIES), and there are a few other ones in terms of sums of other sequences, I couldn't find one with an explicit form like this.
Apr 27, 2016 at 11:34 comment added Alex Degtyarev There are several similar "closed" formulas (in terms of sums) in OEIS.
Apr 27, 2016 at 11:32 comment added Juan Sebastian Lozano Two reasons: 1) I didn't know if this was known, since I couldn't find it anywhere, and I wanted to see if it was even correct, and 2) as a reference for anyone (like me) who might be looking for the answer. I think that's pretty much why SE lets you answer your own questions.
Apr 27, 2016 at 11:23 comment added Todd Leason You posted this answer along with your question in the same minute. So I wonder why you actually asked the question if you already had the answer ?
Apr 27, 2016 at 10:34 history answered Juan Sebastian Lozano CC BY-SA 3.0