Timeline for Modified interlacing of eigenvalues
Current License: CC BY-SA 3.0
14 events
when toggle format | what | by | license | comment | |
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Apr 29, 2016 at 4:50 | vote | accept | Sry | ||
Apr 28, 2016 at 21:40 | answer | added | Nik Weaver | timeline score: 1 | |
Apr 27, 2016 at 15:17 | comment | added | Nik Weaver | Okay, I misread the problem. I don't know the answer, but did you notice that you could put $B = 2v$ without changing nonzero eigenvalues? So the question is about interlacing between $\left[\matrix{A& v\cr v^T&0}\right]$ and $\left[\matrix{A& 2v\cr 2v^T& 0}\right]$. | |
Apr 27, 2016 at 7:24 | comment | added | Sry | I have edited the question to be more elaborated. Yesterday also I put those details in a comment but that comment is no more visible and I don't know why :( | |
Apr 27, 2016 at 7:16 | history | edited | Sry | CC BY-SA 3.0 |
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Apr 27, 2016 at 7:07 | comment | added | Sry | Yes, It can be zero. In particular, take $A=0$ and $A$ is a $n$ order principal submatrix of $D$. I don't understand why you took $n\le4$ | |
Apr 26, 2016 at 16:09 | comment | added | Nik Weaver | $P$ is any order $n$ principal submatrix of $D$ $\ldots$ so if $n \leq 4$, could $P$ be the zero matrix? | |
Apr 26, 2016 at 7:50 | history | edited | Sry | CC BY-SA 3.0 |
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Apr 26, 2016 at 7:33 | history | edited | Sry | CC BY-SA 3.0 |
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S Apr 25, 2016 at 13:54 | history | suggested | Amir Sagiv |
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Apr 25, 2016 at 13:32 | review | Suggested edits | |||
S Apr 25, 2016 at 13:54 | |||||
Apr 25, 2016 at 12:32 | history | edited | Sry | CC BY-SA 3.0 |
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Apr 25, 2016 at 12:11 | review | First posts | |||
Apr 25, 2016 at 12:33 | |||||
Apr 25, 2016 at 12:03 | history | asked | Sry | CC BY-SA 3.0 |