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May 6, 2010 at 16:04 comment added David E Speyer The error is no more.
May 6, 2010 at 16:01 comment added Robin Chapman Let's try to orient this surface. Suppose that $abc$ "goes clockwise". Then so do $acd$, $ade$, $bed$, $bce$ and $acb$. So $abc$ goes both clockwise and anticlockwise. :-)
May 6, 2010 at 15:58 comment added David E Speyer That's an error in Wikipedia. The condition should be that the neighbouring edges are pointing in opposite directions. (Draw a picture.)
May 6, 2010 at 15:55 comment added user4676 I am totally confused now. A total order $a<b<c<d<e<f$ on $\{a,b,c,d,e,f\}$ gives in particular an orientation of all the $2$-simplices. Now (see Wikipedia on orientability) "Any surface has a triangulation (...) Each triangle is oriented by choosing a direction around the perimeter of the triangle, associating a direction to each edge of the triangle. If this is done in such a way that, when glued together, neighboring edges are pointing in the same direction, then this determines an orientation of the surface. Such a choice is only possible if the surface is orientable,(...)".
May 6, 2010 at 14:27 history answered Robin Chapman CC BY-SA 2.5