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Apr 13, 2017 at 12:19 history edited CommunityBot
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Apr 21, 2016 at 17:52 comment added Paul Siegel In the case where the multiplicity is bigger than 1, then which one are you going to pick? You are asking if some function is continuous, but you haven't actually defined a function yet. Come to think of it, the question doesn't even make sense if the multiplicity is equal to 1: even if you impose the constraint that the eigenvector have norm 1, there are still two choices (which differ by a minus sign).
Apr 20, 2016 at 23:52 history edited billbob CC BY-SA 3.0
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Apr 20, 2016 at 23:07 comment added billbob I mean an eigenvector associated with the largest eigenvalue. In the case where this eigenvalue has algebraic multiplicity >1, you would just pick one of the associated eigenvectors.
Apr 20, 2016 at 22:33 comment added Paul Siegel What do you mean by "the first eigenvectors of $P$ and $Q$"? The point is that the eigenprojections are uniquely determined by the symmetric matrix but unless we assume that the eigenspaces are all one dimensional then the eigenvectors are not, even after normalization.
Apr 20, 2016 at 20:00 history edited billbob
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S Apr 20, 2016 at 8:10 history suggested Amir Sagiv CC BY-SA 3.0
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Apr 20, 2016 at 8:04
Apr 20, 2016 at 7:39 history asked billbob CC BY-SA 3.0