Timeline for Two similar integrals
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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S Apr 28, 2016 at 8:01 | history | bounty ended | CommunityBot | ||
S Apr 28, 2016 at 8:01 | history | notice removed | CommunityBot | ||
Apr 21, 2016 at 18:19 | answer | added | Pietro Majer | timeline score: 3 | |
Apr 21, 2016 at 4:54 | history | edited | user173856 | CC BY-SA 3.0 |
added 20 characters in body
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Apr 21, 2016 at 4:51 | comment | added | user173856 | I am sorry. I made a mistake and I have corrected it. | |
Apr 20, 2016 at 18:38 | comment | added | Igor Khavkine | There's something odd about the first identity. The product $\prod_{1\le i < j \le n} (x_i - y_j)$ gives a polynomial of order $n(n-1)/2$ in the $x_i$ and $y_j$. But multiplying $n$ copies of the product $\prod_{j=1}^n (x-y_j)$ from the inner integral to the $n$-power gives a polynomial of order $n^2$ in the $x_i$ and $y_j$. So the two integrals are not obviously equal term by term. Is the first identity actually correct? | |
Apr 20, 2016 at 12:11 | history | edited | Venkataramana | CC BY-SA 3.0 |
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S Apr 20, 2016 at 11:14 | history | suggested | Amir Sagiv |
added the "specific calculation" tag
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Apr 20, 2016 at 11:00 | review | Suggested edits | |||
S Apr 20, 2016 at 11:14 | |||||
Apr 20, 2016 at 8:17 | comment | added | Mircea | "i" seems to indicate sometimes an integer and sometimes the square root of -1, is that true? also the first formula you wrote has maybe to many integrals inside the parenthesis? | |
S Apr 20, 2016 at 6:50 | history | bounty started | user173856 | ||
S Apr 20, 2016 at 6:50 | history | notice added | user173856 | Authoritative reference needed | |
Apr 18, 2016 at 5:22 | history | asked | user173856 | CC BY-SA 3.0 |