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Apr 18, 2016 at 20:01 vote accept CommunityBot
Apr 18, 2016 at 16:45 answer added Mikhail Borovoi timeline score: 0
Apr 18, 2016 at 6:26 comment added Mikhail Borovoi No. Take $G=\mathrm{G}_{m,\mathbb{Q}}\cdot R_{F/\mathbb{Q}}\mathrm{SL}_{2,F}$, where $F$ is a totally real extension of $\mathbb{Q}$. Here $g=[F:\mathbb{Q}]$.
Apr 17, 2016 at 18:46 history edited user70064 CC BY-SA 3.0
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Apr 17, 2016 at 18:32 history asked user70064 CC BY-SA 3.0