Skip to main content
10 events
when toggle format what by license comment
Apr 16, 2016 at 11:57 comment added majid arezoomand Yes, you are right. I should edit my comment. I think that I should replace $S_{p^n}$ with $S_\Omega$, where $\Omega$ is arbitrary.
Apr 16, 2016 at 11:35 comment added Geoff Robinson But it was already noted in my comment that a minimal transitive subgroup of $S_{p^{n}}$ is necessarily a $p$-group anyway.
Apr 16, 2016 at 11:21 comment added majid arezoomand @ GeoffRobinson : Your proof works for the the more general case of nilpotent subgroups of $S_{p^n}$. I mean that we can say that a transitive nilpotent subgroup of $S_{p^n}$ is a minimal transitive subgroup if and only if each point-stabilizer contained in the Frattini subgroup.
Apr 16, 2016 at 10:52 comment added majid arezoomand Dear Prof. Robinson, Thank you very much for your exact answer.
Apr 15, 2016 at 13:18 history edited Geoff Robinson CC BY-SA 3.0
expanded answer
Apr 15, 2016 at 12:31 history edited Geoff Robinson CC BY-SA 3.0
typo
Apr 15, 2016 at 12:11 history edited Geoff Robinson CC BY-SA 3.0
Comment on $p$-power case.
Apr 15, 2016 at 11:57 history undeleted Geoff Robinson
Apr 14, 2016 at 19:09 history deleted Geoff Robinson via Vote
Apr 14, 2016 at 19:08 history answered Geoff Robinson CC BY-SA 3.0