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Apr 18, 2016 at 8:54 vote accept quarague
Apr 15, 2016 at 9:42 comment added Sebastian Goette @ThomasRot This would not work well for manifolds where the boundary is not totally geodesic. For example, if you take the double of the flat unit disk, then two points on the boundary would have two minimizing geodesics between them, one on each part. Neither would the exponential map at a boundary point be injective. So with that definition, you get $0$ again. If you just ask for a unique minimizer, there is no trouble. Schick's definition seems to work as well, but gives $1$ (coming from injectivity of the collar) unless I misinterpreted the statement.
Apr 15, 2016 at 7:26 history edited quarague CC BY-SA 3.0
summmarizing the ideas so far
S Apr 14, 2016 at 13:04 history suggested Amir Sagiv
Added the definitions tag
Apr 14, 2016 at 12:42 review Suggested edits
S Apr 14, 2016 at 13:04
Apr 14, 2016 at 10:17 comment added Anton Petrunin The paper "Geometric curvature bounds in Riemannian manifolds with boundary" by Alexander, Berg and Bishop is related. In particular, it follows a lower bound on your unique-length-minimizer-injectivity radius from upper curvature bound and second fundamental form of the boundary. ams.org/journals/tran/1993-339-02/S0002-9947-1993-1113693-1/…
Apr 14, 2016 at 9:12 answer added user44172 timeline score: 8
Apr 14, 2016 at 7:22 comment added Thomas Rot Maybe one should define it as the injectivity radius of the double of the manifold?
Apr 14, 2016 at 6:48 history asked quarague CC BY-SA 3.0