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Apr 13, 2016 at 21:03 comment added YCor Dense surface subgroups in $\mathrm{PSL}_2(\mathbf{Q}_p)$ were previously known. A closed surface subgroup in $\mathrm{PSL}_2(\mathbf{Q}_p)$ is necessarily dense, and many arithmetic surface groups lie in $\mathrm{PSL}_2$ of some real quadratic extension of $\mathbf{Q}$, and this fits in $\mathbf{Q}_p$ for many values of $p$.
Apr 13, 2016 at 18:53 comment added Dylan Thurston Thanks! That's great. I will study the paper. You do have to be careful about losing faithfulness when passing to a sub-tree, so I think you'll need the dense argument. (For instance, your original free group action might fix a vertex of the tree.)
Apr 13, 2016 at 18:51 vote accept Dylan Thurston
Apr 13, 2016 at 18:35 history answered Uri Bader CC BY-SA 3.0