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May 11, 2023 at 21:06 answer added Federico Poloni timeline score: 3
May 11, 2023 at 19:53 history edited Rodrigo de Azevedo CC BY-SA 4.0
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S Jun 9, 2017 at 18:14 history suggested Pietro Paparella CC BY-SA 3.0
Stochastic matrices are, by definition, nonnegative.
Jun 9, 2017 at 17:51 review Suggested edits
S Jun 9, 2017 at 18:14
Jun 9, 2017 at 17:44 answer added David E Speyer timeline score: 3
Jun 9, 2017 at 17:35 answer added Pietro Paparella timeline score: 2
Apr 14, 2016 at 0:45 history undeleted Gerry Myerson
Todd Trimble
Apr 12, 2016 at 4:28 history deleted tarski via Vote
Apr 12, 2016 at 4:14 history edited tarski CC BY-SA 3.0
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Apr 12, 2016 at 3:55 answer added Gerry Myerson timeline score: 6
Apr 12, 2016 at 3:53 history edited tarski
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Apr 12, 2016 at 3:42 history edited tarski CC BY-SA 3.0
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Apr 12, 2016 at 3:12 history edited tarski CC BY-SA 3.0
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Apr 12, 2016 at 3:10 comment added tarski @GerryMyerson, but if you make said change it becomes a permutation matrix.
Apr 12, 2016 at 2:55 comment added Gerry Myerson @Bill, that's not stochastic (but if you change the last row to $[0,0,1]$, it is).
Apr 12, 2016 at 2:37 comment added Bill Bradley The matrix [[0,1,0],[1,0,0],[0,0,0]] meets your description (it has an eigenvalue of -1), but I'm guessing that's not what you intended. Maybe you want to require the eigenvalue to be non-real?
Apr 12, 2016 at 1:18 history edited tarski CC BY-SA 3.0
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Apr 12, 2016 at 1:04 history edited tarski CC BY-SA 3.0
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Apr 12, 2016 at 0:57 history edited tarski CC BY-SA 3.0
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Apr 12, 2016 at 0:46 history edited tarski CC BY-SA 3.0
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Apr 12, 2016 at 0:42 review First posts
Apr 12, 2016 at 0:47
Apr 12, 2016 at 0:41 history asked tarski CC BY-SA 3.0