Timeline for Tableaux with limited rows and complementary skew shapes
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
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| Mar 2, 2017 at 22:20 | comment | added | darij grinberg | This problem has now reached AoPS: artofproblemsolving.com/community/… | |
| Apr 14, 2016 at 14:34 | answer | added | Pavel Galashin | timeline score: 4 | |
| Apr 14, 2016 at 10:03 | answer | added | Fedor Petrov | timeline score: 1 | |
| Apr 12, 2016 at 19:01 | history | edited | Jordan | CC BY-SA 3.0 |
deleted 10 characters in body
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| Apr 10, 2016 at 19:10 | comment | added | Jordan | I added an example to clarify. | |
| Apr 10, 2016 at 19:09 | history | edited | Jordan | CC BY-SA 3.0 |
added 188 characters in body
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| Apr 10, 2016 at 18:31 | comment | added | Jordan | Typos fixed! Should say $\mu_1-\mu_d$ and the line is $y=0$. Sorry, thanks for catching them! | |
| Apr 10, 2016 at 18:28 | history | edited | Jordan | CC BY-SA 3.0 |
typos
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| Apr 10, 2016 at 3:23 | comment | added | Per Alexandersson | There must be some mistake in your formulation, $\mu_d - \mu_1$ is negative... but now I see what you mean... | |
| Apr 9, 2016 at 23:18 | history | edited | Jordan | CC BY-SA 3.0 |
added 286 characters in body
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| Apr 9, 2016 at 23:11 | comment | added | Jordan | The skew parts are complements in a rectangle, but there is no restriction on the shape of the rest of the tableaux (other they have at most $d$ rows). | |
| Apr 9, 2016 at 11:16 | comment | added | Per Alexandersson | There is an easy bijection if you restrict the numbers to be between $1$ and $\mu_1$ - the column $i$ in $\bar{\mu}$ contains the complement of the elements in column $d-i$ in $\mu$, or did I misinterpret the question? | |
| Apr 9, 2016 at 3:48 | history | asked | Jordan | CC BY-SA 3.0 |