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Mar 9, 2017 at 15:51 comment added Salvatore Siciliano If the ground field has positive characteristic and $L$ is not finitely generated, I suspect that this is not the case. However, I do not have the counterexample.
Mar 9, 2017 at 13:55 comment added YCor By the way, does your condition that $Der(L)$ consists of nilpotent maps imply that $Der(L)$ is nilpotent? I'm not sure about positive characteristic.
Mar 9, 2017 at 10:30 history edited Salvatore Siciliano CC BY-SA 3.0
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Apr 10, 2016 at 17:11 history edited Salvatore Siciliano CC BY-SA 3.0
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Apr 10, 2016 at 15:52 comment added Salvatore Siciliano I just realized that if the derivations of L are nilpotent of bounded index, then Der(L) clairly satisfies an Engel condition and so it is locally nilpotent (indeed nilpotent in case of characteristic 0) by a celebrated result of Zelmanov.
Apr 8, 2016 at 16:03 comment added YCor In the definition of An-Ca, it's clear that char nilpotent implies that the Lie algebra of derivations is nilpotent (since it acts faithfully on the Lie algebra, preserving a finite filtration and acting by identity on successive quotients).
Apr 8, 2016 at 15:00 comment added Salvatore Siciliano OK, thanks. What happens by using the definition of characteristically nilpotent Lie algebra as in the survey of Ancochea-Campoamor instead of the pointwise one? Of course, by the Engel-Jacobson Theorem, in the finite-dimensional case these definitions are equivalent, but in the infinite dimensional case the pointwise one is weaker.
Apr 8, 2016 at 14:39 comment added YCor Well, probably a direct sum of finite-dimensional characteristically nilpotent Lie algebras of nilpotency length tending to infinity can yield a characteristically nilpotent Lie algebra (in the "pointwise" meaning you give) that is not nilpotent modulo its center (and hence has non-nilpotent inner derivation algebra). (This would disprove one implication of the equivalence you mention, but not in the direction of your last question)
Apr 8, 2016 at 14:35 comment added Salvatore Siciliano Yves: The definition of "characteristically nilpotent" is already included, and I am interested in Lie algebras defined over arbitrary fields.
S Apr 8, 2016 at 13:12 history suggested Martin Sleziak CC BY-SA 3.0
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Apr 8, 2016 at 13:07 comment added YCor 1) You haven't defined "characteristically nilpotent", I see 2 possible meanings, in terms of automorphisms, and in terms of derivations (which are equivalent for finite-dimensional Lie algebras in characteristic zero) 2) you haven't specified the ground field, possibly you have in mind the complex field, or arbitrary characteristic... please could you fix this?
Apr 8, 2016 at 12:47 review Suggested edits
S Apr 8, 2016 at 13:12
Apr 8, 2016 at 12:00 history edited Salvatore Siciliano CC BY-SA 3.0
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Apr 8, 2016 at 11:43 history edited Salvatore Siciliano CC BY-SA 3.0
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Apr 8, 2016 at 11:19 history asked Salvatore Siciliano CC BY-SA 3.0