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Apr 8, 2016 at 17:10 comment added Omar Antolín-Camarena Why is this on hold? What is unclear? Is it just because M. Onat wrote "fibration" instead of "fiber sequence" (it's true, as @AlexDegtyarev pointed out, that you might as well assume that $BH \to BG$ is a fibration, but then the question is whether the homotopy fiber is equivalent to $G/H$)?
Apr 8, 2016 at 16:55 review Reopen votes
Apr 8, 2016 at 20:45
Apr 8, 2016 at 16:34 history edited Mehmet Onat CC BY-SA 3.0
added 361 characters in body
Apr 8, 2016 at 15:43 history closed Alex Degtyarev
Alexey Ustinov
Jan-Christoph Schlage-Puchta
Franz Lemmermeyer
Moritz Firsching
Needs details or clarity
Apr 8, 2016 at 12:20 vote accept Mehmet Onat
Apr 8, 2016 at 8:16 comment added Mehmet Onat $G$ is any compact topological group. not Lie group
Apr 7, 2016 at 18:20 comment added Omar Antolín-Camarena This question shows I definitely need some more hypothesis for parts of this question.
Apr 7, 2016 at 14:25 answer added Tyler Lawson timeline score: 5
Apr 7, 2016 at 13:55 comment added Helene Sigloch Do you have arbitrary compact topological groups? Do you have compact Lie groups? Which kind of fibration do you ask for?
Apr 7, 2016 at 13:49 review Close votes
Apr 8, 2016 at 15:43
Apr 7, 2016 at 13:31 comment added Alex Degtyarev What is the difference between fiber bundle and fibration? $B$ is defined up to homotopy equivalence only, and, up to that, any map is a fibration.
Apr 7, 2016 at 13:02 history edited Stefan Kohl CC BY-SA 3.0
Language editing.
Apr 7, 2016 at 12:59 review First posts
Apr 7, 2016 at 13:07
Apr 7, 2016 at 12:57 history asked Mehmet Onat CC BY-SA 3.0