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Jun 17, 2022 at 1:51 comment added Charles Zeilberger & Zudilin now beat Salikhov on the irrationality measure: arxiv.org/abs/1912.06345
Sep 26, 2018 at 11:48 comment added Jeppe Stig Nielsen That was what I thought. Even if the irrationality measure and entire continued-fraction expansion are "easy" for $\sqrt2$, we still do not know much.
Sep 26, 2018 at 0:17 comment added Gerry Myerson @Jeppe, similar remarks apply: it is widely believed (but not proved) that every finite string of digits occurs in the decimal expansion of $\sqrt2$, and furthermore occurs, in the long run, "as often as it should," and furthermore that the analogous statement is true for expansion in base b for b = 2, 3, .... On the other hand, for all we are able to prove, $\sqrt2$ in decimal could be all sixes and sevens (say) from some point on. But, same as for $\pi$, it can't have too long a string of zeros too early.
Sep 25, 2018 at 22:56 comment added Jeppe Stig Nielsen Then, does $\sqrt{2}$, a much more mundane irrational number, contain 1000 consecutive zeroes?
Feb 26, 2018 at 8:40 comment added Gerry Myerson @Patrick, nope.
Feb 26, 2018 at 7:00 comment added PatrickT Can this help at all? en.wikipedia.org/wiki/…
May 21, 2010 at 4:18 comment added Gerry Myerson @Charles, thanks for the link to the Hata paper.
May 21, 2010 at 4:05 comment added Charles matwbn.icm.edu.pl/ksiazki/aa/aa63/aa6344.pdf
May 6, 2010 at 11:53 comment added Wadim Zudilin @Gerry: Thanks for reminding me of why the zeroes should be far away.
May 5, 2010 at 15:56 vote accept Tony Huynh
May 5, 2010 at 6:08 comment added Wadim Zudilin As for the irrationality measure of $\pi$ Hata's longstanding record was recently beat: V.Kh. Salikhov, Russ. Math. Surv. 63, No. 3, 570-572 (2008); translation from Usp. Mat. Nauk 63, No. 3, 163-164 (2008).
May 5, 2010 at 6:02 history answered Gerry Myerson CC BY-SA 2.5