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Jul 20, 2016 at 20:59 vote accept Sylvain JULIEN
Apr 7, 2016 at 13:16 comment added Nate Eldredge One way to have such a result would be to show that a subsequence converges to a particular limit. Iosif Pinelis's LLN example is of this form. Another similar example would be to show that the sequence converges in a weaker topology.
Apr 7, 2016 at 13:05 answer added Ryan O'Donnell timeline score: 4
Apr 7, 2016 at 0:19 comment added Terry Tao Not quite of this form, but zero-one laws are certainly famous: en.wikipedia.org/wiki/Zero%E2%80%93one_law
Apr 6, 2016 at 23:10 comment added Gerry Myerson On a much lower level, if the limit of the sequence $$\sqrt2,\sqrt2^{\sqrt2},\sqrt2^{\sqrt2^{\sqrt2}},\dots$$ exists, then it must be a solution of $\sqrt2^x=x$, hence, 2 (or 4).
Apr 6, 2016 at 20:33 answer added Iosif Pinelis timeline score: 6
Apr 6, 2016 at 20:17 comment added Steve Huntsman See section 2 of cs.toronto.edu/~yuvalf/CLT.pdf (also perhaps books.google.com/books?id=Q4XzBwAAQBAJ as mentioned in section 10 of the PDF), from which I quote: "the real content of the central limit theorem is that convergence does take place. The exact form of the basin of attraction is deducible beforehand - the only question is whether summing up lots of independent variables and normalizing them accordingly would get us closer and closer to the only possible limit, a normal distribution with the limiting mean and variance."
Apr 6, 2016 at 19:26 history edited Stefan Kohl CC BY-SA 3.0
Fixed a typo.
Apr 6, 2016 at 19:23 history asked Sylvain JULIEN CC BY-SA 3.0