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Jun 24 at 22:28 history edited Omar Antolín-Camarena CC BY-SA 4.0
Fixed link to proof
Feb 28, 2018 at 6:47 history edited Omar Antolín-Camarena CC BY-SA 3.0
updated broken URL
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Apr 22, 2016 at 22:48 vote accept Omar Antolín-Camarena
Apr 7, 2016 at 18:23 history edited Omar Antolín-Camarena CC BY-SA 3.0
added guess for missing hypothesis
Apr 6, 2016 at 23:56 answer added Mike-Doherty timeline score: 4
Apr 6, 2016 at 22:01 history edited Omar Antolín-Camarena CC BY-SA 3.0
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Apr 6, 2016 at 21:58 comment added Omar Antolín-Camarena Well, all definitions should be equivalent so I don't really see how it matters, @ViditNanda, but let's say the homotopy fiber over $y_0$ of a map $g : X \to Y$ is the (homotopy type of the) space $\{ (x,p) \in X \times Y^{[0,1]} : p(0) = y_0, p(1) = g(x)\}$. The point is that it is a notion defined for arbitrary maps between spaces, if in the special case of a map $Bf : BG \to BH$ it admits an equivalent description as a classifying space of a category, then I'd say that requires some argument.
Apr 6, 2016 at 21:39 comment added Vidit Nanda @OmarAntolín-Camarena So just to confirm, what is your preferred definition of the homotopy fiber of $Bf$?
Apr 6, 2016 at 21:08 comment added Omar Antolín-Camarena @ViditNanda: Well, (1) it does follow from that, but you'd need to prove that :); (2) I think your characterization is easy to prove if G and H are discrete, is it also easy in general?
Apr 6, 2016 at 20:58 comment added Vidit Nanda I don't have a reference, but doesn't an answer to the first question follow from the fact that the homotopy fiber of $Bf$ is the classifying space of a category whose objects are elements of $H$ and morphisms $h \to h'$ consist of $g \in G$ so that $f(g)h' = h$?
Apr 6, 2016 at 20:53 comment added Omar Antolín-Camarena Borel sounds pretty likely, @RyanBudney.
Apr 6, 2016 at 20:38 comment added Ryan Budney I'm interested in the answers as well but I imagine they all go back to at least Borel, perhaps earlier.
Apr 6, 2016 at 19:15 history edited Omar Antolín-Camarena CC BY-SA 3.0
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Apr 6, 2016 at 18:48 history asked Omar Antolín-Camarena CC BY-SA 3.0