Timeline for Signs in Chevalley's commutator formula
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 27, 2023 at 23:06 | comment | added | LSpice | I am confused about the statement that we can order the simple roots so that the bilinear form is invariant under diagram automorphisms. Suppose that we are in type $\mathsf A_2$. Then, however we number them, there is a diagram automorphism switching $\alpha_1$ and $\alpha_2$, but $B(\alpha_1, \alpha_2) = 0$, while $B(\alpha_2, \alpha_1) = -1$. | |
| Mar 30, 2016 at 14:13 | history | answered | Marty | CC BY-SA 3.0 |