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Mar 30, 2016 at 15:19 vote accept Henry Yuen
Mar 30, 2016 at 14:37 comment added Henry Yuen Do you have a more precise estimate of the error (as a function of $d$) when you try to treat the elements of $\psi$ as independent Gaussians?
Mar 30, 2016 at 14:28 comment added Carlo Beenakker for the first formula, see equation B5 of arxiv.org/abs/cond-mat/9612179 ; measure of concentration: for large $d$ the elements of $\psi$ are independent Gaussians (zero mean, variance $1/d$)
Mar 30, 2016 at 14:22 comment added Henry Yuen Great, thanks! Where did you get the first formula, though? Also, as a followup: would you know what kind of measure of concentration is satisfied by these inner products? That is, what is the probability that $\mathrm{Tr}( \psi \psi^* \, \, w x^* \,\, \psi \psi^* \,\, y z^*)$ deviates from the average by more than some amount $\epsilon$?
Mar 30, 2016 at 12:29 history edited Carlo Beenakker CC BY-SA 3.0
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Mar 30, 2016 at 11:45 history edited Carlo Beenakker CC BY-SA 3.0
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Mar 30, 2016 at 8:37 history edited Carlo Beenakker CC BY-SA 3.0
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Mar 30, 2016 at 8:29 history edited Carlo Beenakker CC BY-SA 3.0
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Mar 30, 2016 at 8:24 history answered Carlo Beenakker CC BY-SA 3.0