Skip to main content
4 events
when toggle format what by license comment
Mar 30, 2016 at 6:06 comment added Simon Rose Well... I think that depends on the definition of $GL_2Z$ being used. I've been thinking of this as $GL_2Z = \{A \in M_2Z \mid \det A = \pm 1\}$, in which case that is a different relation. But as David points out below, it's still the wrong relation, so the point is kind of moot.
Mar 29, 2016 at 22:34 comment added Kevin Casto Notice that your second equivalence relation is just $(X,Y) \sim (k^{-1}X, kY)$, which is just the same as the action of scalar matrices, so you don't gain anything by quotienting by it.
Mar 29, 2016 at 14:26 answer added David E Speyer timeline score: 15
Mar 29, 2016 at 14:01 history asked Simon Rose CC BY-SA 3.0