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Mar 28, 2016 at 9:33 comment added Ben McKay Biholomorphisms of a complex $n$-dimensional manifold depend on $2n$ functions of $n$ variables, while our function $f$ is one essentially arbitrary function of $2n$ variables, so it seems unlikely that a biholomorphism can identify such metrics. Of course, this isn't a rigorous argument. But $f$ can have compact support here, so it is easy to make a rigorous argument.
Mar 28, 2016 at 9:24 comment added Sebastian Goette Is it clear that the new metric is not biholomorphic to the old one?
Mar 27, 2016 at 20:44 history edited Ben McKay CC BY-SA 3.0
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Mar 27, 2016 at 20:26 history answered Ben McKay CC BY-SA 3.0