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May 4, 2010 at 17:41 comment added Dan Ramras For example, there are semi-direct products in which the action is non-trivial, and yet the group is isomorphic to a direct product. This happens if you let $H$ act on $G$ by inner automorphisms of $G$: if $H$ acts through a map $f:G \rightarrow H$, then the isomorphism $G \rtimes H \rightarrow G \times H$ sends $(g,h)$ to $(g f(h), h)$.
May 4, 2010 at 17:24 history answered Mariano Suárez-Álvarez CC BY-SA 2.5