Timeline for Non-completeness of the Borel-Lebesgue measure and countable choice
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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Mar 25, 2016 at 23:38 | vote | accept | Michael | ||
S Mar 25, 2016 at 5:59 | history | suggested | Ed Dean |
just adding [lo.logic] tag
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Mar 25, 2016 at 5:43 | answer | added | Joel David Hamkins | timeline score: 5 | |
Mar 25, 2016 at 5:26 | review | Suggested edits | |||
S Mar 25, 2016 at 5:59 | |||||
Mar 25, 2016 at 5:09 | comment | added | Nate Eldredge | Surely all you have to do is prove that not all sets are Borel. The same proof will go through for the Cantor set, so you get a non-Borel subset of the Cantor set, which is null and hence Lebesgue measurable. | |
Mar 25, 2016 at 4:52 | review | First posts | |||
Mar 25, 2016 at 6:00 | |||||
Mar 25, 2016 at 4:49 | history | asked | Michael | CC BY-SA 3.0 |