Timeline for Are Hilbert-Schmidt operators on separable Hilbert spaces "Hilbert Schmidt" on the space of Hilbert Schmidt Operators?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 11, 2017 at 16:40 | vote | accept | Obriareos | ||
| Mar 11, 2017 at 16:40 | |||||
| Jun 20, 2016 at 16:18 | vote | accept | Obriareos | ||
| Jun 20, 2016 at 16:18 | |||||
| Mar 24, 2016 at 16:48 | comment | added | André Henriques | The bar indicates that I take the complex conjugate. When working over the real numbers, $\overline H = H$. | |
| Mar 24, 2016 at 9:59 | comment | added | Obriareos | Thank you very much André! Just to make sure: I work on hilbert spaces on $\mathbb R.$ I've got some questions: 1. I'm not familiar with the tensor product - I googled it, but why is it important? 2. What do you mean with $\bar{H}$ ? 3. Projections of infinite rank automatically are'nt Hilbert-Schmidt? I have an idea, but I am not 100% sure! | |
| Mar 23, 2016 at 9:31 | history | answered | André Henriques | CC BY-SA 3.0 |