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Mar 25, 2016 at 8:55 comment added user89292 That is very helpful, thanks again.
Mar 24, 2016 at 11:02 comment added Uri Bader On the other hand, if you put assumptions on your measure classes you might get some non-trivial restrictions. For example, if your class is stationary (wrt a generating probability measure on $\Gamma$) then it already must be $\Gamma$-invariant (this follows from the metric-ergodicity of the Furstenberg-Poisson boundary). This puts you back in the setting of your question (and its answer).
Mar 24, 2016 at 11:01 comment added Uri Bader Finding a probability measure whose class is invariant (even ergodic) is just too easy. For example you can find such a measure on $\Gamma$ itself (a positive summable to 1 function), fix a point $x\in X$ and push your measure via the orbit map. No assumption on the representation here. I suppose that there is no reasonable classification of invariant classes on $X$, even under strong assumptions on $X$ and the $\Gamma$-representation.
Mar 24, 2016 at 10:52 history edited Uri Bader CC BY-SA 3.0
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Mar 24, 2016 at 8:56 comment added user89292 by the way @user89334 do you have any idea if it is possible to find a probability measure whose class is preserved instead?
Mar 24, 2016 at 8:54 vote accept user89292
Mar 24, 2016 at 8:17 history edited Uri Bader CC BY-SA 3.0
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Mar 23, 2016 at 15:44 history edited Uri Bader CC BY-SA 3.0
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Mar 23, 2016 at 15:38 history edited Uri Bader CC BY-SA 3.0
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Mar 23, 2016 at 9:01 review First posts
Mar 23, 2016 at 9:05
Mar 23, 2016 at 8:58 history answered Uri Bader CC BY-SA 3.0