Timeline for Is this a characterization of commutative $C^{*}$ algebras?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Mar 23, 2016 at 13:32 | comment | added | Chris Heunen | Ah, thanks Rasmus, I had indeed wrongly read the assumption as saying that self-adjoints commute. | |
| Mar 23, 2016 at 11:47 | comment | added | Rasmus | @ChrisHeunen: I guess positivity is needed to take the square root that makes the proof work. (Notice that OP's assumption is not that self-adjoint elements commute but that $ab$ is self-adjoint iff $ba$ is.) | |
| Mar 23, 2016 at 9:33 | comment | added | Chris Heunen | Isn't it quicker to observe that any element is a linear combination of (two) self-adjoint ones? | |
| Mar 22, 2016 at 22:56 | vote | accept | Ali Taghavi | ||
| Mar 22, 2016 at 22:34 | history | answered | Nik Weaver | CC BY-SA 3.0 |