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Mar 24, 2016 at 7:50 vote accept Dominic van der Zypen
Mar 23, 2016 at 16:33 answer added Lajos Soukup timeline score: 9
Mar 22, 2016 at 19:45 vote accept Dominic van der Zypen
Mar 24, 2016 at 7:50
Mar 22, 2016 at 18:19 answer added Lajos Soukup timeline score: 10
Mar 22, 2016 at 16:47 answer added Will Brian timeline score: 13
Mar 22, 2016 at 16:23 comment added Todd Trimble @WillBrian Thanks! That's interesting. It might be good for someone to lay it all out in an answer, since not everyone seems to have access to the paper cited by Lajos.
Mar 22, 2016 at 16:13 comment added Will Brian @ToddTrimble: You are right -- somehow I failed to notice. At any rate, the paper mentioned by Lajos still answers the question: Proposition 3.2 says that we do not get any such topologies on a countable set, and Corollary 3.4 says that (consistently) we do not get any such topologies on a set of size $\aleph_1$. So the paper shows that the answer to Dominic's first question is yes for some sets and no for some others, and for some we don't seem to know.
Mar 22, 2016 at 15:37 comment added Todd Trimble I don't see how Will's first comment answers the question. Wasn't the problem to show this for any infinite set, not just some infinite set?
Mar 22, 2016 at 15:25 comment added Will Brian @LajosSoukup: I encourage you to post your comment as an answer. It seems that Corollary 3.8 in the paper you found answers Dominic's first question. After a little poking around, I think the second question might be open (and reasonably difficult).
Mar 22, 2016 at 15:00 comment added Dominic van der Zypen Thanks - can somebody of \{Lajos, Will\} post their comments in an answer? Of course it would be great to have an answer to the particular case $X=\mathbb{R}$, but your hints were already really helpful
Mar 22, 2016 at 14:05 comment added Will Brian The paper mentioned by Lajos answers your first question: the authors show that there are two topologies on a set of size $2^{2^{\aleph_0}}$ (both are realizations of the space $\omega^* = \beta \omega - \omega$) whose intersection is precisely the cofinite sets. They don't seem to answer your second question, but there are some relevant-looking results, so you'll want to take a look.
Mar 22, 2016 at 13:54 comment added Todd Trimble This paper might also be useful: sciencedirect.com/science/article/pii/S0166864111003336 I haven't read far enough into it to see whether it definitively answers your question.
Mar 22, 2016 at 13:18 comment added Dominic van der Zypen Thanks a lot @LajosSoukup . I don't have access to that paper, do you know whether there is something on $T_2$-topologies in particular?
Mar 22, 2016 at 13:13 comment added Lajos Soukup If $\tau_1$ and $\tau_2$ meet your requirement, then they are called $T_1$-independent. The following paper may contain useful information: Shakhmatov, D.; Tkachenko, M.; Wilson, R. G. Transversal and T1-independent topologies. Houston J. Math. 30 (2004), no. 2, 421–433.
Mar 22, 2016 at 11:05 comment added Dominic van der Zypen @SimonHenry No worries - I missed that point, too...
Mar 22, 2016 at 10:55 history edited Dominic van der Zypen CC BY-SA 3.0
included cofinite sets
Mar 22, 2016 at 10:54 comment added Dominic van der Zypen Oh right - thanks for this hint! Will edit the question accordingly.
Mar 22, 2016 at 10:48 comment added Will Brian Every $T_1$ topology contains every cofinite set, so being "as disjoint as possible" means at least including all of these.
Mar 22, 2016 at 10:24 comment added Dominic van der Zypen Cool - can you jot down an example as an answer?
Mar 22, 2016 at 8:44 history asked Dominic van der Zypen CC BY-SA 3.0