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Mar 31, 2016 at 17:48 comment added Igor Rivin @Lembik I think that might be partly due to a desire on their part to get provable bounds...
Mar 31, 2016 at 16:17 comment added Simd This is a shame as you can naively approximate the sum from below by only looking at vectors $x$ with small coefficients (say -$x_i \in \{-2,-1,0,1,2\}$). This seems to run in roughly the same amount of time and be accurate to within a few decimal places. In other words, it appears the naive approach is almost as good.
Mar 31, 2016 at 16:12 comment added Igor Rivin @Lembik If you read the paper, you will see that the radius GROWS with $g$ (which is basically the dimension), and since the number of evaluations is something like $R^g,$ the running time will be superexponential. Presumably this cannot really be helped.
Mar 31, 2016 at 14:58 comment added Simd It was essentially identical to the code at github.com/abelfunctions/abelfunctions/issues/121 .
Mar 31, 2016 at 9:15 comment added Igor Rivin @Lembik what was the exact code you ran?
Mar 31, 2016 at 6:19 comment added Simd For anyone interested, I tried the code as implemented at github.com/abelfunctions/abelfunctions/wiki/Getting%20Started and it is very slow. About 10 seconds for a 9 by 9 matrix and too slow to compute for a 12 by 12 matrix. I don't know if the version implemented by Mathematica is much faster as I don't have access to it.
Mar 21, 2016 at 9:48 vote accept Simd
Mar 20, 2016 at 22:53 comment added Branimir Ćaćić In your case, $S_M = \Theta\left(0 \vert \tfrac{1}{\pi} i M\right)$, where $\tfrac{1}{\pi} i M$ is indeed complex symmetric with strictly positive definite imaginary part.
Mar 20, 2016 at 21:16 comment added Simd Thank you for this. Please excuse my ignorance but would you be able explicitly to show an example? The Riemann theta function seems to require that $Im(\Omega)$ is strictly positive definite but my matrix $M$ is real. mathoverflow.net/questions/64261/… shows that there is a Maple function RiemannTheta. How would you use it in my case? Or equivalently, how would you use the Mathematica function SiegelTheta?
Mar 20, 2016 at 19:48 history answered Igor Rivin CC BY-SA 3.0