Timeline for Constructing a polygon of $n$ facets from a set of positive values representing the length of the facets [closed]
Current License: CC BY-SA 3.0
9 events
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Mar 20, 2016 at 5:49 | history | closed |
Ilya Bogdanov Wolfgang Alex Degtyarev Alexey Ustinov Ryan Budney |
Not suitable for this site | |
Mar 17, 2016 at 18:58 | review | Close votes | |||
Mar 20, 2016 at 5:49 | |||||
Mar 17, 2016 at 9:12 | vote | accept | P. Bu. | ||
Mar 17, 2016 at 6:59 | answer | added | Manfred Weis | timeline score: 1 | |
Mar 17, 2016 at 6:41 | comment | added | Fedor Petrov | Another result in this direction is that under above necessary condition there exists unique cyclic polygon with given sides (in given order). | |
Mar 17, 2016 at 0:30 | comment | added | Joseph O'Rourke | See the earlier related MO question and answer here, which cites references. The condition you mention allows not only construction of a polygon, but of a convex polygon, and in fact, a triangle. | |
Mar 17, 2016 at 0:03 | comment | added | Fedor Petrov | Of course it is enough. You may do it by induction: having (convex) $(n-1)$-gon with sides $a_1, a_2,\dots,a_{n-2},a_{n-1}+a_n$ we may replace triangle with sides $a_{n-1}+a_n,a_{n-2}$ and some third size $x$ to a quadrilateral with sides $x,a_{n-2},a_{n-1},a_n$, which is a union of two triangles with sides $a_{n-1}+a_n-\varepsilon,a_{n-2},x$ and $a_{n-1}+a_n-\varepsilon$, $a_{n-1},a_n$. | |
Mar 16, 2016 at 23:55 | comment | added | Steve Huntsman | As an aside, projecteuclid.org/euclid.jdg/1214457034 discusses the relevant moduli space | |
Mar 16, 2016 at 23:42 | history | asked | P. Bu. | CC BY-SA 3.0 |