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screwed up... meant to say current.
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$P=I^2 \times R$ as in Power = The current squared times the resistance.

In this case the square root is the actual powercurrent flowing through the device. This is particularly useful in situations with low transconductance power mos-fets and the heat they would have to dissipate in high performance industrial situations, with 1000-10,000 amp welders and platers.

$P=I^2 \times R$ as in Power = The current squared times the resistance.

In this case the square root is the actual power. This is particularly useful in situations with low transconductance power mos-fets and the heat they would have to dissipate in high performance industrial situations, with 1000-10,000 amp welders and platers.

$P=I^2 \times R$ as in Power = The current squared times the resistance.

In this case the square root is the actual current flowing through the device. This is particularly useful in situations with low transconductance power mos-fets and the heat they would have to dissipate in high performance industrial situations, with 1000-10,000 amp welders and platers.

+latex
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Myshkin
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P=I**2 x R$P=I^2 \times R$ as in Power = The current squared times the resistance. 

In this case the square root is the actual power. This is particularly useful in situations with low transconductance power mos-fets and the heat they would have to dissipate in high performance industrial situations, with 1000-10,000 amp welders and platers.

P=I**2 x R as in Power = The current squared times the resistance. In this case the square root is the actual power. This is particularly useful in situations with low transconductance power mos-fets and the heat they would have to dissipate in high performance industrial situations, with 1000-10,000 amp welders and platers.

$P=I^2 \times R$ as in Power = The current squared times the resistance. 

In this case the square root is the actual power. This is particularly useful in situations with low transconductance power mos-fets and the heat they would have to dissipate in high performance industrial situations, with 1000-10,000 amp welders and platers.

Source Link

P=I**2 x R as in Power = The current squared times the resistance. In this case the square root is the actual power. This is particularly useful in situations with low transconductance power mos-fets and the heat they would have to dissipate in high performance industrial situations, with 1000-10,000 amp welders and platers.

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