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Robert Israel
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I don't know about "physically driven", but you could try

$$\ddot{u} + 4 t \dot{u} + (4 t^2 + 3) u = 0$$

If you want something autonomous, you might make it

$$ \eqalign{\ddot{u} + 4 v \dot{u} + (4 v^2 + 3) u &= 0 \cr \dot{v} & = 1\cr}$$

which can be made into a single nonlinear d.e., but it will be messy.

I don't know about "physically driven", but you could try

$$\ddot{u} + 4 t \dot{u} + (4 t^2 + 3) u = 0$$

I don't know about "physically driven", but you could try

$$\ddot{u} + 4 t \dot{u} + (4 t^2 + 3) u = 0$$

If you want something autonomous, you might make it

$$ \eqalign{\ddot{u} + 4 v \dot{u} + (4 v^2 + 3) u &= 0 \cr \dot{v} & = 1\cr}$$

which can be made into a single nonlinear d.e., but it will be messy.

added 4 characters in body
Source Link
Robert Israel
  • 54.2k
  • 1
  • 76
  • 152

I don't know about "physically driven", but you could try

$$\ddot{u} + 4 t \dot{u} + (4 t^2 + 3) u = 0$$

I don't know about "physically driven", but you could try

$$\ddot{u} + 4 t \dot{u} + (4 t^2 + 3) u = 0$$

I don't know about "physically driven", but you could try

$$\ddot{u} + 4 t \dot{u} + (4 t^2 + 3) u = 0$$

Source Link
Robert Israel
  • 54.2k
  • 1
  • 76
  • 152

I don't know about "physically driven", but you could try

$$\ddot{u} + 4 t \dot{u} + (4 t^2 + 3) u = 0$$