Timeline for combinatorics on cyclic sequences
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Apr 1, 2016 at 11:26 | history | bounty ended | Darío G | ||
| S Apr 1, 2016 at 11:26 | history | notice removed | Darío G | ||
| Mar 26, 2016 at 16:17 | vote | accept | Darío G | ||
| Mar 26, 2016 at 9:50 | answer | added | Moritz Firsching | timeline score: 6 | |
| S Mar 26, 2016 at 8:19 | history | bounty started | Darío G | ||
| S Mar 26, 2016 at 8:19 | history | notice added | Darío G | Draw attention | |
| S Mar 24, 2016 at 22:50 | history | bounty ended | CommunityBot | ||
| S Mar 24, 2016 at 22:50 | history | notice removed | CommunityBot | ||
| Mar 18, 2016 at 14:57 | comment | added | Darío G | @JonMarkPerry If $k=1$, then a position $j$ is $2b$ iff $a_j=0$. Since an interval only has one zero at the end, then the element before is $1g1b$. for instance, if the interval ends with $(\ldots,1,0]$ and this 1 is $a_j$, then $U_{1,j}(1)=1$ and $U_{2,j}(1)=0$ (because you start the counting from the position $j$ until the next $0$, which is $a_{j+1}$. | |
| Mar 18, 2016 at 14:37 | comment | added | JMP | why don't bad intervals then end with 2b,...,2b? | |
| Mar 17, 2016 at 15:52 | comment | added | JMP | oh, okay then.. | |
| Mar 17, 2016 at 15:50 | comment | added | Darío G | The definition of good intervals includes at least two elements 2g before the first 1g1b, while the neutral intervals have only one element 2g and then 1g1b. | |
| Mar 17, 2016 at 12:39 | comment | added | JMP | your definition of a good interval invokes that of a neutral one. | |
| S Mar 16, 2016 at 21:17 | history | bounty started | Darío G | ||
| S Mar 16, 2016 at 21:17 | history | notice added | Darío G | Draw attention | |
| Mar 14, 2016 at 13:17 | history | asked | Darío G | CC BY-SA 3.0 |