Timeline for Extending rational Diophantine triples to sextuples
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Mar 13, 2016 at 20:58 | comment | added | Tito Piezas III | Thanks! Your first family also has, $$(a+b-c)^2 = 4(ab+1)$$ and I forgot to specify that when this happens, then one element of the extended "sextuple" is zero, so effectively it is just a quintuple. | |
| Mar 13, 2016 at 20:51 | vote | accept | Tito Piezas III | ||
| Mar 13, 2016 at 20:46 | history | edited | duje | CC BY-SA 3.0 |
added 156 characters in body
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| Mar 13, 2016 at 20:31 | history | answered | duje | CC BY-SA 3.0 |