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Mar 18, 2016 at 8:35 vote accept Saal Hardali
Mar 15, 2016 at 12:27 answer added Andreas Cap timeline score: 11
Mar 11, 2016 at 13:44 comment added Peter Michor See 18.16 (p 225) of mat.univie.ac.at/~michor/dgbook.pdf
Mar 11, 2016 at 13:42 comment added Jason Starr If you are working in the setting of algebraic geometry, you can prove that isomorphism via "faithfully flat descent". If you pullback your exact sequence to $G$, then it is the tangent bundle sequence. Next you check that the induced isomorphism between the pullback to $G$ of $T(G/H)$ and $G\times^H (\mathfrak{g}/\mathfrak{h})$ satisfies a "cocycle condition" after pullback to $G \times_{G/H} G \cong H \times G$. Thus the isomorphism of bundles on $G$ is the pullback of an isomorphism on $G/H$.
Mar 11, 2016 at 13:23 history asked Saal Hardali CC BY-SA 3.0